2700+2580x=2700x-x^2

Solution for 2700+2580x=2700x-x^2 equation:

2700+2580x=2700x-x^2

We move all terms to the left:

2700+2580x-(2700x-x^2)=0

We get rid of parentheses

x^2-2700x+2580x+2700=0

We add all the numbers together, and all the variables

x^2-120x+2700=0

a = 1; b = -120; c = +2700;
Δ = b2-4ac
Δ = -1202-4·1·2700
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-60}{2*1}=\frac{60}{2}
=30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+60}{2*1}=\frac{180}{2}
=90
$